# Closure semantics¶

The `xtensor`

library is a tensor expression library implementing numpy-style broadcasting and universal functions, but in a lazy fashion.

If `x`

and `y`

are two tensor expressions with compatible shapes, the result of `x + y`

is not a tensor but an expression that does
not hold any value. Values of `x + y`

are computed upon access or when the result is assigned to a container such as `xt::xtensor`

or
`xt::xarray`

. The same holds for most functions in xtensor, views, broadcasting views, etc.

In order to be able to perform the differed computation of `x + y`

, the returned expression must hold references, const references or
copies of the members `x`

and `y`

, depending on how arguments were passed to `operator+`

. The actual types of held by the expressions
are the **closure types**.

The concept of closure type is key in the implementation of `xtensor`

and appears in all the expressions defined in xtensor, and the
utility functions and meta functions complements the tools of the standard libary for the move semantics.

## Basic rules for determinning closure types¶

The two main requirements are the following:

- when an argument passed to the function returning an expression (here,
`operator+`

) is an*rvalue*, the closure type is always a value and the`rvalue`

is*moved*. - when an argument passed to the function returning an expression is an
*lvalue reference*, the closure type is a reference of the same type.

It is important for the closure type not to be a reference when the passed argument is an rvalue, which can result in dangling references.

Following the conventions of the C++ standard library for naming type traits, we provide two type traits classes providing an implementation of these rules
in the `xutils.hpp`

header, `closure`

, and `const_closure`

. The latter adds the const qualifier even when the provided argument is not const.

```
template <class S>
struct closure
{
using underlying_type = std::conditional_t<
std::is_const<std::remove_reference_t<S>>::value,
const std::decay_t<S>,
std::decay_t<S>>;
using type = typename std::conditional<
std::is_lvalue_reference<S>::value,
underlying_type&,
underlying_type>::type;
};
template <class S>
using closure_t = typename closure<S>::type;
```

The implementation for `const_closure`

is slightly shorter.

```
template <class S>
struct const_closure
{
using underlying_type = const std::decay_t<S>;
using type = typename std::conditional<
std::is_lvalue_reference<S>::value,
underlying_type&,
underlying_type>::type;
};
template <class S>
using const_closure_t = typename const_closure<S>::type;
```

Using this mechanism, we were able to

- avoid dangling references in nested expressions,
- hold references whenever possible,
- take advantage of the move semantics when holding references is not possible.

## Closure types and scalar wrappers¶

A requirement for `xtensor`

is the ability to mix scalars and tensors in tensor expressions. In order to do so,
scalar values are wrapped into the `xscalar`

wrapper, which is a cheap 0-D tensor expression holding a single
scalar value.

For the xscalar to be a proper proxy on the scalar value, if actually holds a closure type on the scalar value.

The logics for this is encoded into xtensor’s `xclosure`

type trait.

```
template <class E, class EN = void>
struct xclosure
{
using type = closure_t<E>;
};
template <class E>
struct xclosure<E, disable_xexpression<std::decay_t<E>>>
{
using type = xscalar<closure_t<E>>;
};
template <class E>
using xclosure_t = typename xclosure<E>::type;
```

In doing so, we ensure const-correctness, we avoid dangling reference, and ensure that lvalues remain lvalues. The const_xclosure follows the same scheme:

```
template <class E, class EN = void>
struct const_xclosure
{
using type = const_closure_t<E>;
};
template <class E>
struct const_xclosure<E, disable_xexpression<std::decay_t<E>>>
{
using type = xscalar<std::decay_t<E>>;
};
template <class E>
using const_xclosure_t = typename const_xclosure<E>::type;
```

## Writing functions that return expressions¶

*xtensor closure semantics are not meant to prevent users from doing mistakes, since it would also prevent them from doing something clever*.

This section covers cases where understanding C++ move semantics and xtensor closure semantics helps writing better code with xtensor.

### Returning evaluated or unevaluated expressions¶

A key feature of xtensor is that a function returning e.g. `x + y / z`

where `x`

, `y`

and `z`

are xtensor expressions does not actually perform any
computation. It is only evaluated upon access or assignment. The returned expression holds values or references for `x`

, `y`

and `z`

depending on the
lvalue-ness of the variables passed to the expression, using the *closure semantics* described earlier. This may result in dangling references when using
local variables of a function in an unevaluated expression, unless one properly forwards / move the variables.

Note

The following rule of thumbs prevents dangling references in the xtensor closure semantics:

- If the laziness is not important for your usecase, returning
`xt::eval(x + y / z)`

will return an evaluated container and avoid these complications. - Otherwise, the key is to
*move*lvalues that become invalid when leaving the current scope.

**Example: moving local variables and forwarding universal references**

Let us first consider the following implementation of the `mean`

function in xtensor:

```
template <class E>
inline auto mean(E&& e) noexcept
{
using value_type = typename std::decay_t<E>::value_type;
auto size = e.size();
auto s = sum(std::forward<E>(e));
return std::move(s) / value_type(size);
}
```

The first thing to take into account is that the result of the final division is an expression, which performs the actual computation upon access or assignent.

- In order to perform the division, the expression must hold the values or references on the numerator and denominator.
- Since
`s`

is a local variable, it will be destroyed upon leaving the scope of the function, and more importantly it is an*lvalue*. - A consequence of
`s`

being an lvalue and a local variable, is that the`s / value_type(size)`

would end up holding a dangling const reference on`s`

. - Hence we must call return
`std::move(s) / value_type(size)`

.

The other place in this example where the C++ move semantics is used is the line `s = sum(std::forward<E>(e))`

. The goal is to have the unevaluated `s`

expression
hold a const reference or a value for `e`

depending on the lvalue-ness of the parameter passed to the function.